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{(x,y)|x+y = 5} is a
  • a)
    not a function
  • b)
    a composite function
  • c)
    one-one mapping
  • d)
    none of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
{(x,y)|x+y = 5} is aa)not a functionb)a composite functionc)one-one ma...
To determine the nature of the set (x, y)| xy = 5, consider the following:

  • The set represents a hyperbola, where any x has a unique corresponding y = {5/x}.

  • Each pair (x, y) satisfies the relation xy = 5, implying a one-to-one correspondence between x and y.

  • This mapping is both injective and bijective, as each x maps to exactly one y and vice versa

  •  
Thus, the correct answer is Option C: one-one mapping.
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Most Upvoted Answer
{(x,y)|x+y = 5} is aa)not a functionb)a composite functionc)one-one ma...
Explanation:

Given set {(x,y)|x y = 5}

To understand the properties of this set, we need to convert it into a function.

A function is a relation between two sets, where each element of the first set is related to exactly one element of the second set.

Let's consider the set {(x,y)|x y = 5} as a relation between two sets X and Y.

X = {x| x is a real number}

Y = {y| y is a real number}

Now, let's check whether this relation is a function or not.

To be a function, each element of set X should be related to exactly one element of set Y.

If we take x = 1, then y can be either 5 or 1/5. Hence, x is related to two elements of set Y, which violates the definition of a function.

Therefore, the given set {(x,y)|x y = 5} is not a function.

But, it can be converted into a one-to-one mapping.

One-to-One Mapping:

A one-to-one mapping is a function where each element of set X is related to one and only one element of set Y.

To make the given set {(x,y)|x y = 5} a one-to-one mapping, we need to restrict the domain and range of the sets X and Y.

Let's restrict X to {x| x > 0} and Y to {y| y > 0}.

Now, if we take any element x from X, it will be related to only one element y from Y, and vice versa.

Hence, the given set {(x,y)|x y = 5} is a one-to-one mapping.
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