{(x,y)|x+y = 5} is aa)not a functionb)a composite functionc)one-one ma...
To determine the nature of the set (x, y)| xy = 5, consider the following:
- The set represents a hyperbola, where any x has a unique corresponding y = {5/x}.
- Each pair (x, y) satisfies the relation xy = 5, implying a one-to-one correspondence between x and y.
- This mapping is both injective and bijective, as each x maps to exactly one y and vice versa
Thus, the correct answer is Option C: one-one mapping.
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{(x,y)|x+y = 5} is aa)not a functionb)a composite functionc)one-one ma...
Explanation:
Given set {(x,y)|x y = 5}
To understand the properties of this set, we need to convert it into a function.
A function is a relation between two sets, where each element of the first set is related to exactly one element of the second set.
Let's consider the set {(x,y)|x y = 5} as a relation between two sets X and Y.
X = {x| x is a real number}
Y = {y| y is a real number}
Now, let's check whether this relation is a function or not.
To be a function, each element of set X should be related to exactly one element of set Y.
If we take x = 1, then y can be either 5 or 1/5. Hence, x is related to two elements of set Y, which violates the definition of a function.
Therefore, the given set {(x,y)|x y = 5} is not a function.
But, it can be converted into a one-to-one mapping.
One-to-One Mapping:
A one-to-one mapping is a function where each element of set X is related to one and only one element of set Y.
To make the given set {(x,y)|x y = 5} a one-to-one mapping, we need to restrict the domain and range of the sets X and Y.
Let's restrict X to {x| x > 0} and Y to {y| y > 0}.
Now, if we take any element x from X, it will be related to only one element y from Y, and vice versa.
Hence, the given set {(x,y)|x y = 5} is a one-to-one mapping.
{(x,y)|x+y = 5} is aa)not a functionb)a composite functionc)one-one ma...